3.7.18 \(\int \frac {x^4 (a+b x^2)^2}{\sqrt {c+d x^2}} \, dx\)

Optimal. Leaf size=194 \[ \frac {c^2 \left (48 a^2 d^2+5 b c (7 b c-16 a d)\right ) \tanh ^{-1}\left (\frac {\sqrt {d} x}{\sqrt {c+d x^2}}\right )}{128 d^{9/2}}-\frac {c x \sqrt {c+d x^2} \left (48 a^2 d^2+5 b c (7 b c-16 a d)\right )}{128 d^4}+\frac {x^3 \sqrt {c+d x^2} \left (48 a^2 d^2+5 b c (7 b c-16 a d)\right )}{192 d^3}-\frac {b x^5 \sqrt {c+d x^2} (7 b c-16 a d)}{48 d^2}+\frac {b^2 x^7 \sqrt {c+d x^2}}{8 d} \]

________________________________________________________________________________________

Rubi [A]  time = 0.15, antiderivative size = 194, normalized size of antiderivative = 1.00, number of steps used = 6, number of rules used = 5, integrand size = 24, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.208, Rules used = {464, 459, 321, 217, 206} \begin {gather*} \frac {c^2 \left (48 a^2 d^2+5 b c (7 b c-16 a d)\right ) \tanh ^{-1}\left (\frac {\sqrt {d} x}{\sqrt {c+d x^2}}\right )}{128 d^{9/2}}+\frac {x^3 \sqrt {c+d x^2} \left (48 a^2+\frac {5 b c (7 b c-16 a d)}{d^2}\right )}{192 d}-\frac {c x \sqrt {c+d x^2} \left (48 a^2 d^2+5 b c (7 b c-16 a d)\right )}{128 d^4}-\frac {b x^5 \sqrt {c+d x^2} (7 b c-16 a d)}{48 d^2}+\frac {b^2 x^7 \sqrt {c+d x^2}}{8 d} \end {gather*}

Antiderivative was successfully verified.

[In]

Int[(x^4*(a + b*x^2)^2)/Sqrt[c + d*x^2],x]

[Out]

-(c*(48*a^2*d^2 + 5*b*c*(7*b*c - 16*a*d))*x*Sqrt[c + d*x^2])/(128*d^4) + ((48*a^2 + (5*b*c*(7*b*c - 16*a*d))/d
^2)*x^3*Sqrt[c + d*x^2])/(192*d) - (b*(7*b*c - 16*a*d)*x^5*Sqrt[c + d*x^2])/(48*d^2) + (b^2*x^7*Sqrt[c + d*x^2
])/(8*d) + (c^2*(48*a^2*d^2 + 5*b*c*(7*b*c - 16*a*d))*ArcTanh[(Sqrt[d]*x)/Sqrt[c + d*x^2]])/(128*d^(9/2))

Rule 206

Int[((a_) + (b_.)*(x_)^2)^(-1), x_Symbol] :> Simp[(1*ArcTanh[(Rt[-b, 2]*x)/Rt[a, 2]])/(Rt[a, 2]*Rt[-b, 2]), x]
/; FreeQ[{a, b}, x] && NegQ[a/b] && (GtQ[a, 0] || LtQ[b, 0])

Rule 217

Int[1/Sqrt[(a_) + (b_.)*(x_)^2], x_Symbol] :> Subst[Int[1/(1 - b*x^2), x], x, x/Sqrt[a + b*x^2]] /; FreeQ[{a,
b}, x] &&  !GtQ[a, 0]

Rule 321

Int[((c_.)*(x_))^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(c^(n - 1)*(c*x)^(m - n + 1)*(a + b*x^n
)^(p + 1))/(b*(m + n*p + 1)), x] - Dist[(a*c^n*(m - n + 1))/(b*(m + n*p + 1)), Int[(c*x)^(m - n)*(a + b*x^n)^p
, x], x] /; FreeQ[{a, b, c, p}, x] && IGtQ[n, 0] && GtQ[m, n - 1] && NeQ[m + n*p + 1, 0] && IntBinomialQ[a, b,
c, n, m, p, x]

Rule 459

Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_.)*((c_) + (d_.)*(x_)^(n_)), x_Symbol] :> Simp[(d*(e*x)^(m
+ 1)*(a + b*x^n)^(p + 1))/(b*e*(m + n*(p + 1) + 1)), x] - Dist[(a*d*(m + 1) - b*c*(m + n*(p + 1) + 1))/(b*(m +
n*(p + 1) + 1)), Int[(e*x)^m*(a + b*x^n)^p, x], x] /; FreeQ[{a, b, c, d, e, m, n, p}, x] && NeQ[b*c - a*d, 0]
&& NeQ[m + n*(p + 1) + 1, 0]

Rule 464

Int[((e_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_)*((c_) + (d_.)*(x_)^(n_))^2, x_Symbol] :> Simp[(d^2*(e*x)^
(m + n + 1)*(a + b*x^n)^(p + 1))/(b*e^(n + 1)*(m + n*(p + 2) + 1)), x] + Dist[1/(b*(m + n*(p + 2) + 1)), Int[(
e*x)^m*(a + b*x^n)^p*Simp[b*c^2*(m + n*(p + 2) + 1) + d*((2*b*c - a*d)*(m + n + 1) + 2*b*c*n*(p + 1))*x^n, x],
x], x] /; FreeQ[{a, b, c, d, e, m, n, p}, x] && NeQ[b*c - a*d, 0] && IGtQ[n, 0] && NeQ[m + n*(p + 2) + 1, 0]

Rubi steps

\begin {align*} \int \frac {x^4 \left (a+b x^2\right )^2}{\sqrt {c+d x^2}} \, dx &=\frac {b^2 x^7 \sqrt {c+d x^2}}{8 d}+\frac {\int \frac {x^4 \left (8 a^2 d-b (7 b c-16 a d) x^2\right )}{\sqrt {c+d x^2}} \, dx}{8 d}\\ &=-\frac {b (7 b c-16 a d) x^5 \sqrt {c+d x^2}}{48 d^2}+\frac {b^2 x^7 \sqrt {c+d x^2}}{8 d}-\frac {1}{48} \left (-48 a^2-\frac {5 b c (7 b c-16 a d)}{d^2}\right ) \int \frac {x^4}{\sqrt {c+d x^2}} \, dx\\ &=\frac {\left (48 a^2+\frac {5 b c (7 b c-16 a d)}{d^2}\right ) x^3 \sqrt {c+d x^2}}{192 d}-\frac {b (7 b c-16 a d) x^5 \sqrt {c+d x^2}}{48 d^2}+\frac {b^2 x^7 \sqrt {c+d x^2}}{8 d}-\frac {\left (c \left (48 a^2+\frac {5 b c (7 b c-16 a d)}{d^2}\right )\right ) \int \frac {x^2}{\sqrt {c+d x^2}} \, dx}{64 d}\\ &=-\frac {c \left (48 a^2+\frac {5 b c (7 b c-16 a d)}{d^2}\right ) x \sqrt {c+d x^2}}{128 d^2}+\frac {\left (48 a^2+\frac {5 b c (7 b c-16 a d)}{d^2}\right ) x^3 \sqrt {c+d x^2}}{192 d}-\frac {b (7 b c-16 a d) x^5 \sqrt {c+d x^2}}{48 d^2}+\frac {b^2 x^7 \sqrt {c+d x^2}}{8 d}+\frac {\left (c^2 \left (48 a^2+\frac {5 b c (7 b c-16 a d)}{d^2}\right )\right ) \int \frac {1}{\sqrt {c+d x^2}} \, dx}{128 d^2}\\ &=-\frac {c \left (48 a^2+\frac {5 b c (7 b c-16 a d)}{d^2}\right ) x \sqrt {c+d x^2}}{128 d^2}+\frac {\left (48 a^2+\frac {5 b c (7 b c-16 a d)}{d^2}\right ) x^3 \sqrt {c+d x^2}}{192 d}-\frac {b (7 b c-16 a d) x^5 \sqrt {c+d x^2}}{48 d^2}+\frac {b^2 x^7 \sqrt {c+d x^2}}{8 d}+\frac {\left (c^2 \left (48 a^2+\frac {5 b c (7 b c-16 a d)}{d^2}\right )\right ) \operatorname {Subst}\left (\int \frac {1}{1-d x^2} \, dx,x,\frac {x}{\sqrt {c+d x^2}}\right )}{128 d^2}\\ &=-\frac {c \left (48 a^2+\frac {5 b c (7 b c-16 a d)}{d^2}\right ) x \sqrt {c+d x^2}}{128 d^2}+\frac {\left (48 a^2+\frac {5 b c (7 b c-16 a d)}{d^2}\right ) x^3 \sqrt {c+d x^2}}{192 d}-\frac {b (7 b c-16 a d) x^5 \sqrt {c+d x^2}}{48 d^2}+\frac {b^2 x^7 \sqrt {c+d x^2}}{8 d}+\frac {c^2 \left (48 a^2+\frac {5 b c (7 b c-16 a d)}{d^2}\right ) \tanh ^{-1}\left (\frac {\sqrt {d} x}{\sqrt {c+d x^2}}\right )}{128 d^{5/2}}\\ \end {align*}

________________________________________________________________________________________

Mathematica [A]  time = 0.16, size = 159, normalized size = 0.82 \begin {gather*} \frac {3 c^2 \left (48 a^2 d^2-80 a b c d+35 b^2 c^2\right ) \log \left (\sqrt {d} \sqrt {c+d x^2}+d x\right )+\sqrt {d} x \sqrt {c+d x^2} \left (48 a^2 d^2 \left (2 d x^2-3 c\right )+16 a b d \left (15 c^2-10 c d x^2+8 d^2 x^4\right )+b^2 \left (-105 c^3+70 c^2 d x^2-56 c d^2 x^4+48 d^3 x^6\right )\right )}{384 d^{9/2}} \end {gather*}

Antiderivative was successfully verified.

[In]

Integrate[(x^4*(a + b*x^2)^2)/Sqrt[c + d*x^2],x]

[Out]

(Sqrt[d]*x*Sqrt[c + d*x^2]*(48*a^2*d^2*(-3*c + 2*d*x^2) + 16*a*b*d*(15*c^2 - 10*c*d*x^2 + 8*d^2*x^4) + b^2*(-1
05*c^3 + 70*c^2*d*x^2 - 56*c*d^2*x^4 + 48*d^3*x^6)) + 3*c^2*(35*b^2*c^2 - 80*a*b*c*d + 48*a^2*d^2)*Log[d*x + S
qrt[d]*Sqrt[c + d*x^2]])/(384*d^(9/2))

________________________________________________________________________________________

IntegrateAlgebraic [A]  time = 0.31, size = 173, normalized size = 0.89 \begin {gather*} \frac {\sqrt {c+d x^2} \left (-144 a^2 c d^2 x+96 a^2 d^3 x^3+240 a b c^2 d x-160 a b c d^2 x^3+128 a b d^3 x^5-105 b^2 c^3 x+70 b^2 c^2 d x^3-56 b^2 c d^2 x^5+48 b^2 d^3 x^7\right )}{384 d^4}+\frac {\left (-48 a^2 c^2 d^2+80 a b c^3 d-35 b^2 c^4\right ) \log \left (\sqrt {c+d x^2}-\sqrt {d} x\right )}{128 d^{9/2}} \end {gather*}

Antiderivative was successfully verified.

[In]

IntegrateAlgebraic[(x^4*(a + b*x^2)^2)/Sqrt[c + d*x^2],x]

[Out]

(Sqrt[c + d*x^2]*(-105*b^2*c^3*x + 240*a*b*c^2*d*x - 144*a^2*c*d^2*x + 70*b^2*c^2*d*x^3 - 160*a*b*c*d^2*x^3 +
96*a^2*d^3*x^3 - 56*b^2*c*d^2*x^5 + 128*a*b*d^3*x^5 + 48*b^2*d^3*x^7))/(384*d^4) + ((-35*b^2*c^4 + 80*a*b*c^3*
d - 48*a^2*c^2*d^2)*Log[-(Sqrt[d]*x) + Sqrt[c + d*x^2]])/(128*d^(9/2))

________________________________________________________________________________________

fricas [A]  time = 1.17, size = 344, normalized size = 1.77 \begin {gather*} \left [\frac {3 \, {\left (35 \, b^{2} c^{4} - 80 \, a b c^{3} d + 48 \, a^{2} c^{2} d^{2}\right )} \sqrt {d} \log \left (-2 \, d x^{2} - 2 \, \sqrt {d x^{2} + c} \sqrt {d} x - c\right ) + 2 \, {\left (48 \, b^{2} d^{4} x^{7} - 8 \, {\left (7 \, b^{2} c d^{3} - 16 \, a b d^{4}\right )} x^{5} + 2 \, {\left (35 \, b^{2} c^{2} d^{2} - 80 \, a b c d^{3} + 48 \, a^{2} d^{4}\right )} x^{3} - 3 \, {\left (35 \, b^{2} c^{3} d - 80 \, a b c^{2} d^{2} + 48 \, a^{2} c d^{3}\right )} x\right )} \sqrt {d x^{2} + c}}{768 \, d^{5}}, -\frac {3 \, {\left (35 \, b^{2} c^{4} - 80 \, a b c^{3} d + 48 \, a^{2} c^{2} d^{2}\right )} \sqrt {-d} \arctan \left (\frac {\sqrt {-d} x}{\sqrt {d x^{2} + c}}\right ) - {\left (48 \, b^{2} d^{4} x^{7} - 8 \, {\left (7 \, b^{2} c d^{3} - 16 \, a b d^{4}\right )} x^{5} + 2 \, {\left (35 \, b^{2} c^{2} d^{2} - 80 \, a b c d^{3} + 48 \, a^{2} d^{4}\right )} x^{3} - 3 \, {\left (35 \, b^{2} c^{3} d - 80 \, a b c^{2} d^{2} + 48 \, a^{2} c d^{3}\right )} x\right )} \sqrt {d x^{2} + c}}{384 \, d^{5}}\right ] \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^4*(b*x^2+a)^2/(d*x^2+c)^(1/2),x, algorithm="fricas")

[Out]

[1/768*(3*(35*b^2*c^4 - 80*a*b*c^3*d + 48*a^2*c^2*d^2)*sqrt(d)*log(-2*d*x^2 - 2*sqrt(d*x^2 + c)*sqrt(d)*x - c)
+ 2*(48*b^2*d^4*x^7 - 8*(7*b^2*c*d^3 - 16*a*b*d^4)*x^5 + 2*(35*b^2*c^2*d^2 - 80*a*b*c*d^3 + 48*a^2*d^4)*x^3 -
3*(35*b^2*c^3*d - 80*a*b*c^2*d^2 + 48*a^2*c*d^3)*x)*sqrt(d*x^2 + c))/d^5, -1/384*(3*(35*b^2*c^4 - 80*a*b*c^3*
d + 48*a^2*c^2*d^2)*sqrt(-d)*arctan(sqrt(-d)*x/sqrt(d*x^2 + c)) - (48*b^2*d^4*x^7 - 8*(7*b^2*c*d^3 - 16*a*b*d^
4)*x^5 + 2*(35*b^2*c^2*d^2 - 80*a*b*c*d^3 + 48*a^2*d^4)*x^3 - 3*(35*b^2*c^3*d - 80*a*b*c^2*d^2 + 48*a^2*c*d^3)
*x)*sqrt(d*x^2 + c))/d^5]

________________________________________________________________________________________

giac [A]  time = 0.41, size = 178, normalized size = 0.92 \begin {gather*} \frac {1}{384} \, {\left (2 \, {\left (4 \, {\left (\frac {6 \, b^{2} x^{2}}{d} - \frac {7 \, b^{2} c d^{5} - 16 \, a b d^{6}}{d^{7}}\right )} x^{2} + \frac {35 \, b^{2} c^{2} d^{4} - 80 \, a b c d^{5} + 48 \, a^{2} d^{6}}{d^{7}}\right )} x^{2} - \frac {3 \, {\left (35 \, b^{2} c^{3} d^{3} - 80 \, a b c^{2} d^{4} + 48 \, a^{2} c d^{5}\right )}}{d^{7}}\right )} \sqrt {d x^{2} + c} x - \frac {{\left (35 \, b^{2} c^{4} - 80 \, a b c^{3} d + 48 \, a^{2} c^{2} d^{2}\right )} \log \left ({\left | -\sqrt {d} x + \sqrt {d x^{2} + c} \right |}\right )}{128 \, d^{\frac {9}{2}}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^4*(b*x^2+a)^2/(d*x^2+c)^(1/2),x, algorithm="giac")

[Out]

1/384*(2*(4*(6*b^2*x^2/d - (7*b^2*c*d^5 - 16*a*b*d^6)/d^7)*x^2 + (35*b^2*c^2*d^4 - 80*a*b*c*d^5 + 48*a^2*d^6)/
d^7)*x^2 - 3*(35*b^2*c^3*d^3 - 80*a*b*c^2*d^4 + 48*a^2*c*d^5)/d^7)*sqrt(d*x^2 + c)*x - 1/128*(35*b^2*c^4 - 80*
a*b*c^3*d + 48*a^2*c^2*d^2)*log(abs(-sqrt(d)*x + sqrt(d*x^2 + c)))/d^(9/2)

________________________________________________________________________________________

maple [A]  time = 0.02, size = 265, normalized size = 1.37 \begin {gather*} \frac {\sqrt {d \,x^{2}+c}\, b^{2} x^{7}}{8 d}+\frac {\sqrt {d \,x^{2}+c}\, a b \,x^{5}}{3 d}-\frac {7 \sqrt {d \,x^{2}+c}\, b^{2} c \,x^{5}}{48 d^{2}}+\frac {\sqrt {d \,x^{2}+c}\, a^{2} x^{3}}{4 d}-\frac {5 \sqrt {d \,x^{2}+c}\, a b c \,x^{3}}{12 d^{2}}+\frac {35 \sqrt {d \,x^{2}+c}\, b^{2} c^{2} x^{3}}{192 d^{3}}+\frac {3 a^{2} c^{2} \ln \left (\sqrt {d}\, x +\sqrt {d \,x^{2}+c}\right )}{8 d^{\frac {5}{2}}}-\frac {5 a b \,c^{3} \ln \left (\sqrt {d}\, x +\sqrt {d \,x^{2}+c}\right )}{8 d^{\frac {7}{2}}}+\frac {35 b^{2} c^{4} \ln \left (\sqrt {d}\, x +\sqrt {d \,x^{2}+c}\right )}{128 d^{\frac {9}{2}}}-\frac {3 \sqrt {d \,x^{2}+c}\, a^{2} c x}{8 d^{2}}+\frac {5 \sqrt {d \,x^{2}+c}\, a b \,c^{2} x}{8 d^{3}}-\frac {35 \sqrt {d \,x^{2}+c}\, b^{2} c^{3} x}{128 d^{4}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^4*(b*x^2+a)^2/(d*x^2+c)^(1/2),x)

[Out]

1/8*b^2*x^7*(d*x^2+c)^(1/2)/d-7/48*b^2*c/d^2*x^5*(d*x^2+c)^(1/2)+35/192*b^2*c^2/d^3*x^3*(d*x^2+c)^(1/2)-35/128
*b^2*c^3/d^4*x*(d*x^2+c)^(1/2)+35/128*b^2*c^4/d^(9/2)*ln(d^(1/2)*x+(d*x^2+c)^(1/2))+1/3*a*b*x^5/d*(d*x^2+c)^(1
/2)-5/12*a*b*c/d^2*x^3*(d*x^2+c)^(1/2)+5/8*a*b*c^2/d^3*x*(d*x^2+c)^(1/2)-5/8*a*b*c^3/d^(7/2)*ln(d^(1/2)*x+(d*x
^2+c)^(1/2))+1/4*a^2*x^3/d*(d*x^2+c)^(1/2)-3/8*a^2*c/d^2*x*(d*x^2+c)^(1/2)+3/8*a^2*c^2/d^(5/2)*ln(d^(1/2)*x+(d
*x^2+c)^(1/2))

________________________________________________________________________________________

maxima [A]  time = 0.94, size = 243, normalized size = 1.25 \begin {gather*} \frac {\sqrt {d x^{2} + c} b^{2} x^{7}}{8 \, d} - \frac {7 \, \sqrt {d x^{2} + c} b^{2} c x^{5}}{48 \, d^{2}} + \frac {\sqrt {d x^{2} + c} a b x^{5}}{3 \, d} + \frac {35 \, \sqrt {d x^{2} + c} b^{2} c^{2} x^{3}}{192 \, d^{3}} - \frac {5 \, \sqrt {d x^{2} + c} a b c x^{3}}{12 \, d^{2}} + \frac {\sqrt {d x^{2} + c} a^{2} x^{3}}{4 \, d} - \frac {35 \, \sqrt {d x^{2} + c} b^{2} c^{3} x}{128 \, d^{4}} + \frac {5 \, \sqrt {d x^{2} + c} a b c^{2} x}{8 \, d^{3}} - \frac {3 \, \sqrt {d x^{2} + c} a^{2} c x}{8 \, d^{2}} + \frac {35 \, b^{2} c^{4} \operatorname {arsinh}\left (\frac {d x}{\sqrt {c d}}\right )}{128 \, d^{\frac {9}{2}}} - \frac {5 \, a b c^{3} \operatorname {arsinh}\left (\frac {d x}{\sqrt {c d}}\right )}{8 \, d^{\frac {7}{2}}} + \frac {3 \, a^{2} c^{2} \operatorname {arsinh}\left (\frac {d x}{\sqrt {c d}}\right )}{8 \, d^{\frac {5}{2}}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^4*(b*x^2+a)^2/(d*x^2+c)^(1/2),x, algorithm="maxima")

[Out]

1/8*sqrt(d*x^2 + c)*b^2*x^7/d - 7/48*sqrt(d*x^2 + c)*b^2*c*x^5/d^2 + 1/3*sqrt(d*x^2 + c)*a*b*x^5/d + 35/192*sq
rt(d*x^2 + c)*b^2*c^2*x^3/d^3 - 5/12*sqrt(d*x^2 + c)*a*b*c*x^3/d^2 + 1/4*sqrt(d*x^2 + c)*a^2*x^3/d - 35/128*sq
rt(d*x^2 + c)*b^2*c^3*x/d^4 + 5/8*sqrt(d*x^2 + c)*a*b*c^2*x/d^3 - 3/8*sqrt(d*x^2 + c)*a^2*c*x/d^2 + 35/128*b^2
*c^4*arcsinh(d*x/sqrt(c*d))/d^(9/2) - 5/8*a*b*c^3*arcsinh(d*x/sqrt(c*d))/d^(7/2) + 3/8*a^2*c^2*arcsinh(d*x/sqr
t(c*d))/d^(5/2)

________________________________________________________________________________________

mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {x^4\,{\left (b\,x^2+a\right )}^2}{\sqrt {d\,x^2+c}} \,d x \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((x^4*(a + b*x^2)^2)/(c + d*x^2)^(1/2),x)

[Out]

int((x^4*(a + b*x^2)^2)/(c + d*x^2)^(1/2), x)

________________________________________________________________________________________

sympy [B]  time = 28.18, size = 422, normalized size = 2.18 \begin {gather*} - \frac {3 a^{2} c^{\frac {3}{2}} x}{8 d^{2} \sqrt {1 + \frac {d x^{2}}{c}}} - \frac {a^{2} \sqrt {c} x^{3}}{8 d \sqrt {1 + \frac {d x^{2}}{c}}} + \frac {3 a^{2} c^{2} \operatorname {asinh}{\left (\frac {\sqrt {d} x}{\sqrt {c}} \right )}}{8 d^{\frac {5}{2}}} + \frac {a^{2} x^{5}}{4 \sqrt {c} \sqrt {1 + \frac {d x^{2}}{c}}} + \frac {5 a b c^{\frac {5}{2}} x}{8 d^{3} \sqrt {1 + \frac {d x^{2}}{c}}} + \frac {5 a b c^{\frac {3}{2}} x^{3}}{24 d^{2} \sqrt {1 + \frac {d x^{2}}{c}}} - \frac {a b \sqrt {c} x^{5}}{12 d \sqrt {1 + \frac {d x^{2}}{c}}} - \frac {5 a b c^{3} \operatorname {asinh}{\left (\frac {\sqrt {d} x}{\sqrt {c}} \right )}}{8 d^{\frac {7}{2}}} + \frac {a b x^{7}}{3 \sqrt {c} \sqrt {1 + \frac {d x^{2}}{c}}} - \frac {35 b^{2} c^{\frac {7}{2}} x}{128 d^{4} \sqrt {1 + \frac {d x^{2}}{c}}} - \frac {35 b^{2} c^{\frac {5}{2}} x^{3}}{384 d^{3} \sqrt {1 + \frac {d x^{2}}{c}}} + \frac {7 b^{2} c^{\frac {3}{2}} x^{5}}{192 d^{2} \sqrt {1 + \frac {d x^{2}}{c}}} - \frac {b^{2} \sqrt {c} x^{7}}{48 d \sqrt {1 + \frac {d x^{2}}{c}}} + \frac {35 b^{2} c^{4} \operatorname {asinh}{\left (\frac {\sqrt {d} x}{\sqrt {c}} \right )}}{128 d^{\frac {9}{2}}} + \frac {b^{2} x^{9}}{8 \sqrt {c} \sqrt {1 + \frac {d x^{2}}{c}}} \end {gather*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**4*(b*x**2+a)**2/(d*x**2+c)**(1/2),x)

[Out]

-3*a**2*c**(3/2)*x/(8*d**2*sqrt(1 + d*x**2/c)) - a**2*sqrt(c)*x**3/(8*d*sqrt(1 + d*x**2/c)) + 3*a**2*c**2*asin
h(sqrt(d)*x/sqrt(c))/(8*d**(5/2)) + a**2*x**5/(4*sqrt(c)*sqrt(1 + d*x**2/c)) + 5*a*b*c**(5/2)*x/(8*d**3*sqrt(1
+ d*x**2/c)) + 5*a*b*c**(3/2)*x**3/(24*d**2*sqrt(1 + d*x**2/c)) - a*b*sqrt(c)*x**5/(12*d*sqrt(1 + d*x**2/c))
- 5*a*b*c**3*asinh(sqrt(d)*x/sqrt(c))/(8*d**(7/2)) + a*b*x**7/(3*sqrt(c)*sqrt(1 + d*x**2/c)) - 35*b**2*c**(7/2
)*x/(128*d**4*sqrt(1 + d*x**2/c)) - 35*b**2*c**(5/2)*x**3/(384*d**3*sqrt(1 + d*x**2/c)) + 7*b**2*c**(3/2)*x**5
/(192*d**2*sqrt(1 + d*x**2/c)) - b**2*sqrt(c)*x**7/(48*d*sqrt(1 + d*x**2/c)) + 35*b**2*c**4*asinh(sqrt(d)*x/sq
rt(c))/(128*d**(9/2)) + b**2*x**9/(8*sqrt(c)*sqrt(1 + d*x**2/c))

________________________________________________________________________________________